Log & Exponent Evaluator

Solve log base 10, ln and custom-base equations

Grades 11–12

Base (b)

Value (x)

Change-of-base formula:

\log_{10}(100) = \frac{\ln(100)}{\ln(10)} = \frac{4.6052}{2.3026} = 2.000000

log₁₀(100) = 2.000000

Verification: 10^2.0000 ≈ 100.0000

Graph: y = log₁₀(x)