Integrals
GradesPre-Calculus & CalculusIntegralsDefinite Integrals & the Fundamental Theorem

Definite Integrals & the Fundamental Theorem

โˆซ Integrals
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Definite Integrals & the Fundamental Theorem

Compute exact areas using the Fundamental Theorem of Calculus.

The definite integral โˆซ_a^b f(x) dx represents the net signed area between the curve y = f(x) and the x-axis from x = a to x = b. The Fundamental Theorem of Calculus (FTC) links differentiation and integration โ€” two seemingly unrelated operations.

โˆซabf(x)โ€‰dx=F(b)โˆ’F(a)whereย Fโ€ฒ(x)=f(x)\int_a^b f(x)\,dx = F(b) - F(a) \quad \text{where } F'(x) = f(x)
FTCย Partย 1:ย ddxโˆซaxf(t)โ€‰dt=f(x)\text{FTC Part 1: } \frac{d}{dx}\int_a^x f(t)\,dt = f(x)

A Riemann sum approximates the definite integral by dividing [a, b] into n subintervals of width ฮ”x = (bโˆ’a)/n and summing the areas of rectangles. As nโ†’โˆž, the Riemann sum converges to the exact integral.

โˆซabf(x)โ€‰dx=limโกnโ†’โˆžโˆ‘i=1nf(xiโˆ—)โ€‰ฮ”x\int_a^b f(x)\,dx = \lim_{n\to\infty}\sum_{i=1}^n f(x_i^*)\,\Delta x
๐Ÿ“Computing a Definite Integral
โˆซโ‚ยณ (xยฒ + 1) dx. F(x) = xยณ/3 + x. F(3) = 9 + 3 = 12. F(1) = 1/3 + 1 = 4/3. Integral = 12 โˆ’ 4/3 = 32/3.
โˆซ13(x2+1)โ€‰dx=[x33+x]13=12โˆ’43=323\int_1^3 (x^2+1)\,dx = \left[\frac{x^3}{3}+x\right]_1^3 = 12 - \frac{4}{3} = \frac{32}{3}
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Remember This!

The notation [F(x)]_a^b means F(b) โˆ’ F(a). Always subtract the value at the lower limit from the value at the upper limit, not the other way around.

โœ๏ธ Try It!

Evaluate โˆซโ‚€ยฒ (3xยฒ โˆ’ 2x) dx.

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