Sketch parabolas using vertex, axis of symmetry, and intercepts.
Every quadratic function y = ax² + bx + c graphs as a parabola. The sign of a tells you which way it opens: if a > 0 the parabola opens upward (happy face ☺); if a < 0 it opens downward (sad face ☹). The vertex is the highest or lowest point.
Axis of symmetry: x = −b / (2a). The vertex x-coordinate is always this value.
Graphing y = ax² + bx + c
a=1, b=−4, c=3. Axis: x = −(−4)/(2·1) = 2. Vertex: y = 4−8+3 = −1, so vertex is (2,−1). y-intercept: (0, 3). x-intercepts: x²−4x+3 = (x−1)(x−3) = 0 → x=1 and x=3.
Standard Form
Vertex Form
Remember This!
The vertex gives the minimum value of the function when a > 0, or the maximum value when a < 0. Real-world problems like "maximum height" of a ball always look for the vertex.
For y = 2x² − 8x + 6, what is the x-coordinate of the vertex?